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Do not munge foreign keys when migrating to enterprises

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This commit is contained in:
Rohan Mitchell
2012-11-02 15:34:02 +11:00
parent 3a116dc13d
commit 80159e1ea7
1 changed files with 12 additions and 3 deletions
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15
db/migrate/20121025012233_combine_suppliers_and_distributors_into_enterprises.rb
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@@ -30,6 +30,7 @@ class CombineSuppliersAndDistributorsIntoEnterprises < ActiveRecord::Migration
end
# Copy suppliers to enterprises table with primary producer flag set
updated_product_ids = [-1]
Supplier.all.each do |s|
attrs = s.attributes
attrs.reject! { |k| k == 'id' }
@@ -37,10 +38,14 @@ class CombineSuppliersAndDistributorsIntoEnterprises < ActiveRecord::Migration
e = Enterprise.create! attrs
# Update supplier_id on product to point at the new enterprise
Spree::Product.update_all("supplier_id=#{e.id}", "supplier_id=#{s.id}")
product_ids = Spree::Product.where(:supplier_id => s.id).pluck(:id)
Spree::Product.update_all("supplier_id=#{e.id}", "supplier_id=#{s.id} AND id NOT IN (#{updated_product_ids.join(', ')})")
updated_product_ids += product_ids
end
# Copy distributors to enterprises table with distributor flag set
updated_product_distribution_ids = [-1]
updated_order_ids = [-1]
Distributor.all.each do |d|
attrs = d.attributes
attrs['website'] = attrs['url']
@@ -49,8 +54,12 @@ class CombineSuppliersAndDistributorsIntoEnterprises < ActiveRecord::Migration
e = Enterprise.create! attrs
# Update distributor_id on product distribution and order to point at the new enterprise
ProductDistribution.update_all("distributor_id=#{e.id}", "distributor_id=#{d.id}")
Spree::Order.update_all("distributor_id=#{e.id}", "distributor_id=#{d.id}")
product_distribution_ids = ProductDistribution.where(:distributor_id => d.id).pluck(:id)
order_ids = Spree::Order.where(:distributor_id => d.id).pluck(:id)
ProductDistribution.update_all("distributor_id=#{e.id}", "distributor_id=#{d.id} AND id NOT IN (#{updated_product_distribution_ids.join(', ')})")
Spree::Order.update_all("distributor_id=#{e.id}", "distributor_id=#{d.id} AND id NOT IN (#{updated_order_ids.join(', ')})")
updated_product_distribution_ids += product_distribution_ids
updated_order_ids += order_ids
end
end